3[2r+1]=15

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Solution for 3[2r+1]=15 equation: 


Simplifying
3[2r + 1] = 15

Reorder the terms:
3[1 + 2r] = 15
[1 * 3 + 2r * 3] = 15
[3 + 6r] = 15

Solving
3 + 6r = 15

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 6r = 15 + -3

Combine like terms: 3 + -3 = 0
0 + 6r = 15 + -3
6r = 15 + -3

Combine like terms: 15 + -3 = 12
6r = 12

Divide each side by '6'.
r = 2

Simplifying
r = 2

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